If the distance from the X-ray source is doubled, the exposure rate becomes what fraction of the original?

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Multiple Choice

If the distance from the X-ray source is doubled, the exposure rate becomes what fraction of the original?

Explanation:
Exposure rate from an X-ray source follows the inverse square relationship: it is proportional to 1 over the distance squared. If you double the distance, the exposure rate becomes (1/(2d)^2) = 1/4 of the original. So the exposure rate is reduced to one quarter of its initial value. In practice, increasing distance greatly reduces exposure at a point, and to maintain the same receptor exposure you would need to increase tube current or exposure time accordingly.

Exposure rate from an X-ray source follows the inverse square relationship: it is proportional to 1 over the distance squared. If you double the distance, the exposure rate becomes (1/(2d)^2) = 1/4 of the original. So the exposure rate is reduced to one quarter of its initial value. In practice, increasing distance greatly reduces exposure at a point, and to maintain the same receptor exposure you would need to increase tube current or exposure time accordingly.

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